{"product_id":"absolute-superman-19-cvr-a-rafa-sandoval","title":"ABSOLUTE SUPERMAN #19 CVR A RAFA SANDOVAL","description":"\u003cdiv class=\"content\"\u003e\n\u003cdiv id=\"returnability\"\u003e\u003c\/div\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv class=\"content\"\u003e\n\u003cdiv id=\"returnability\"\u003e\u003c\/div\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pdesc\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e\n\u003cdiv id=\"pcreators\"\u003e(W) Jason Aaron (A\/CA) Rafa Sandoval\u003c\/div\u003e\n\u003cdiv\u003e\u003c\/div\u003e\n\u003cdiv id=\"pdesc\"\u003eKING SHAZAM IS HERE TO SHATTER THE ABSOLUTE UNIVERSE! King Shazam has risen with a power unlike anything Superman has faced before. What connection does he have to Brainiac and the mysterious Father Box? Plus, another classic character has made their Absolute debut, though it remains to be seen if they're a friend or foe of the Man of Steel...\u003c\/div\u003e\n\u003c\/div\u003e\n\u003cdiv\u003e\u003cbr\u003e\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003cdiv id=\"pdesc\"\u003e\n\u003cp\u003eRelease Date 05\/06\/2026\u003c\/p\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e\n\u003c\/div\u003e","brand":"Glass City Comics \u0026 Collectibles","offers":[{"title":"Default Title","offer_id":53430390325562,"sku":"GC3742","price":4.99,"currency_code":"USD","in_stock":true}],"thumbnail_url":"\/\/cdn.shopify.com\/s\/files\/1\/0938\/0908\/2682\/files\/ASM19A.jpg?v=1778370918","url":"https:\/\/www.glasscitycomics.com\/products\/absolute-superman-19-cvr-a-rafa-sandoval","provider":"Glass City Comics \u0026 Collectibles","version":"1.0","type":"link"}